poj 2187 Beauty Contest

裸题+1

Description

Bessie, Farmer John’s prize cow, has just won first place in a bovine beauty contest, earning the title ‘Miss Cow World’. As a result, Bessie will make a tour of N (2 <= N <= 50,000) farms around the world in order to spread goodwill between farmers and their cows. For simplicity, the world will be represented as a two-dimensional plane, where each farm is located at a pair of integer coordinates (x,y), each having a value in the range -10,000 … 10,000. No two farms share the same pair of coordinates.

Even though Bessie travels directly in a straight line between pairs of farms, the distance between some farms can be quite large, so she wants to bring a suitcase full of hay with her so she has enough food to eat on each leg of her journey. Since Bessie refills her suitcase at every farm she visits, she wants to determine the maximum possible distance she might need to travel so she knows the size of suitcase she must bring.Help Bessie by computing the maximum distance among all pairs of farms.

Input

* Line 1: A single integer, N

* Lines 2..N+1: Two space-separated integers x and y specifying coordinate of each farm
Output

* Line 1: A single integer that is the squared distance between the pair of farms that are farthest apart from each other.
Sample Input

4
0 0
0 1
1 1
1 0
Sample Output

2
Hint

Farm 1 (0, 0) and farm 3 (1, 1) have the longest distance (square root of 2)

裸的旋转卡壳

题解啥的看总结吧

#include <cstdio>
#include <cmath>
#include <cstdlib>
#include <algorithm>
#include <cstring>
#define N 50010
using namespace std;

const double eps=1e-7;
int dcmp(double x)
{
	if (fabs(x)<eps) return 0;
	else
		if (x>0)
			return 1;
		else
			return -1;
}

const double pi=acos(-1.0);

struct Vector
{
	double x,y;
	Vector (double a=0,double b=0)
	{
		x=a,y=b;
	}
	bool operator < (const Vector &a) const
	{
		return x<a.x||(x==a.x&&y<a.y);
	}
};
typedef Vector Point;

struct Line
{
	Point p;
	Vector v;
	Line(Point P=Point(0,0),Vector V=Vector(0,0))
	{
		p=P,v=V;
	}
};

Vector operator + (Vector a,Vector b) {return Vector(a.x+b.x,a.y+b.y);}
Vector operator - (Vector a,Vector b) {return Vector(a.x-b.x,a.y-b.y);}
Vector operator * (Vector a,double b) {return Vector(a.x*b  ,a.y*b  );}
Vector operator / (Vector a,double b) {return Vector(a.x/b  ,a.y/b  );}
bool   operator ==(Vector a,Vector b) {return !dcmp(a.x-b.x)&&!dcmp(a.y-b.y);}

Vector Rotate(Vector a,double rad)
{
	return Vector(a.x*cos(rad)-a.y*sin(rad),a.x*sin(rad)+a.y*cos(rad));
}

double Dot(Vector a,Vector b)
{
    return a.x*b.x+a.y*b.y;
}

double Len(Vector a){return sqrt(Dot(a,a));}

double Angle(Vector a,Vector b){return acos(Dot(a,b)/Len(a)/Len(b));}

double Cross(Vector a,Vector b)
{
    return a.x*b.y-a.y*b.x;
}

Vector Normal(Vector a)
{
    return Vector(-a.y/Len(a),a.x/Len(a));
}

Point Line_cross(Line a,Line b)
{
	Vector u=a.p-b.p;
	double t=Cross(b.v,u)/Cross(a.v,b.v);
	return a.p+a.v*t;
}

double Dis_To_Line(Point p,Point a,Point b)
{
	return fabs(Cross(a-b,p-b)/Len(a-b));
}

double Dis_To_Seg(Point p,Point a,Point b)
{
	if (a==b) return Len(p-a);
	Vector v=b-a,w=p-a,u=p-b;
	if (dcmp(Dot(v,w)<0))	return Len(w);
	else if (dcmp(Dot(v,u))>0)	return Len(v);
	else return fabs(Cross(v,w)/Len(v));
}

bool Line_Seg_Cross(Point l1,Point l2,Point a,Point b)
{
	Vector v=l1-l2,w=a-l1,u=b-l2;
	return dcmp(Cross(v,w))!=dcmp(Cross(v,u));
}

bool Seg_Cross(Point a1,Point a2,Point b1,Point b2)
{
	double c1=Cross(a2-a1,b1-b1),c2=Cross(a2-a1,b2-a1),
	       c3=Cross(b2-b1,a1-b1),c4=Cross(b2-b1,a2-b1);
	return dcmp(c1)*dcmp(c2)<0 && dcmp(c3)*dcmp(c4)<0;
}

Point Line_Pro(Point p,Point a,Point b)
{
	Vector v=b-a;
	return a+v*(Dot(v,p-a)/Dot(v,v));
}

double Area_T(Point a, Point b,Point c)
{
	return Cross(b-a,c-a)*0.5;
}

Point TC(Point a,Point b,Point c)
{
	Point p=(a+b)/2,q=(a+c)/2;
	Vector v=Rotate(b-a,pi/2),w=Rotate(c-a,pi/2);
	if (!dcmp(Cross(v,w)))
	{
        if (dcmp(Len(a-b)+Len(b-c)-Len(a-c))==0)
            return (a+c)/2;
        if (dcmp(Len(a-c)+Len(b-c)-Len(a-b))==0)
            return (a+b)/2;
        if (dcmp(Len(a-b)+Len(a-c)-Len(b-c))==0)
            return (b+c)/2;
    }
    return Line_cross(Line(p,v),Line(q,w));
}

Point TG(Point a,Point b,Point c)
{
    return (a+b+c)/3;
}

double Area_P(Point ploy[],int num)
{
	double area=0;
	for (int i=2;i<num;i++)
		area+=Cross(ploy[i]-ploy[1],ploy[i+1]-ploy[1]);
	return area/2;
}

bool Point_In_Ploy(Point p,Point poly[],int num)
{
	int ans=0,k,d1,d2;
	for (int i=1;i<=num;i++)
	{
		if (!dcmp(Dis_To_Seg(p,poly[i],poly[i%num+1]))) return 0;
		k=dcmp(Cross(poly[i%num+1]-poly[i],p-poly[i]));
		d1=dcmp(poly[i].y-p.y);
		d2=dcmp(poly[i%num+1].y-p.y);
		if (k>0&&d1<=0&&d2>0) ++ans;
		if (k<0&&d1>=0&&d2<0) --ans;
	}
	if (ans) return 1;
	return 0;
}

Point stack[N];int top;
void Graham(Point p[],int num)
{
	memset(stack,0,sizeof stack);top=0;
	sort(p+1,p+num+1);
	for (int i=1;i<=num;i++)
	{
		while (top>1 && dcmp(Cross(stack[top]-stack[top-1],p[i]-stack[top-1]))<=0)
			top--;
		stack[++top]=p[i];
	}
	int k=top;
	for (int i=num-1;i>=1;i--)
	{
		while (top>k && dcmp(Cross(stack[top]-stack[top-1],p[i]-stack[top-1]))<=0)
			top--;
		stack[++top]=p[i];
	}
	if (num>1) top--;
}

double rotating()
{
    if (top==1) return 0;
    if (top==2) return Len(stack[2]-stack[1]);
    int now=1;
    double ans=0;
    for (int i=1;i<=top;++i)
    {
        while (dcmp(Dis_To_Line(stack[now],stack[i],stack[i%top+1])-Dis_To_Line(stack[now%top+1],stack[i],stack[i%top+1]))<=0)
            now=now%top+1;
        ans=max(ans,Len(stack[now]-stack[i]));
        ans=max(ans,Len(stack[now]-stack[i%top+1]));
    }
    return ans;
}

double sqr(double a)
{
	return a*a;
}

int main()
{
	int n;
	scanf("%d",&n);
	double x1,x2,x3,x4,y1,y2,y3,y4;
	Point p[N];
	for (int i=1;i<=n;i++)
		scanf("%lf%lf",&p[i].x,&p[i].y);
	Graham(p,n);
	printf("%d",(int)sqr(rotating()));
}